Please reply with two numbers between 1 and 15 according to the drafting rules.
- Once alignments have been dealt out, each player must pick two whole numbers (this is because someone tried to pick pi last time), between 1 and 15.
The player to pick the first unique number closest to 1 will be first in the draft order. However, if several players pick the same first number, they will all go to the bottom of the draft order. Then I would move on to the next lowest number (in this case, 2) and the same rules apply. If no other player has picked 2 as their first number, then the person who picked 2 will become first in the draft order. This continues until I get to 21 players.
Now, the second number is used to determine who goes first, in the event of players picking the same first number. The lowest number of the second number goes first and so on. In the event players picked the same two numbers, I will once again reset them to the back of the queue (for the order they are in). In the event that your first and second numbers both clash with another player’s numbers, you both go straight to the bottom of the order. So, if three players picked [4][1], [4][1] and [4][7], the two players with [4][1] are bumped below the player that picked [4][7] along with the original bump. Ultimately, the most unique number combination will get priority.
- Here is an example draft:
Lets say the following players choose the following numbers.
Player A - [4][14]
Player B - [1][12]
Player C - [1][6]
Player D - [7][8]
Player E - [3][4]
Player F - [7][8]
Player G - [7][15]
Players B and C both picked 1. They go to the back of the queue. Player E is the next lowest # and the only one that picked 3. He/She goes first. Then player A since He/She is the only one to pick 4. Then Player D would have been next with 7 ahead of B and C, but Player’s F and G also picked 7 so they both go behind Players B and C.
Current Order: Bolded players are locked into position.
Player E
Player A
Player B
Player C
Player D
Player F
Player G
Now I just resolve Players B, C, D,F and G. Between B and C, I look at the second #. B has a 12, C has a 6. So C gets to pick before B.
Current Order: Bolded players are locked into position.
Player E
Player A
Player C
Player B
Player D
Player F
Now between D,F and G they all picked the same 1st numbers [7][?]. So I look at the second number to determine their order. Player G has a different number [7] [15] whereas D and F both have [7][8]. Same rule as before and G gets to pick before D and F.
Player E
Player A
Player C
Player B
Player G
Player D
Player F
In the case of D and F I do a discobot roll to determine who goes first since they have the same 2 numbers. For arguments sake lets say F got a 1 and D got a 3 on a dice roll. F goes before D.
Player E
Player A
Player C
Player B
Player G
Player F
Player D
note: In the case of ties it doesn’t matter how many people picked the same #. If 3 people picked [3][ ] and 2 people picked [7][*] where * is any arbitrary number 3s go before 7s. The order isn’t reset AGAIN per tie.
Simple right? Of course this is all done to create mind traps between Scum and Town for picking #s. Remember once this phase is done you will know what yout draft position. You just wont know what anyone elses draft position is or what roles got picked.
- Once this has happened, each player will send in the “role pair” they’d like to choose thier role from. Only one role from each “pair” will be awarded, for example; there cannot be a Doctor and a Roleblocker in the game.
- As such, in the event multiple players select the same role (or the same “pair”), the player highest in the draft order wins the role, whilst the others remain Vanilla.
- Roles are then distributed.
- Throughout the bidding phases, the thread is locked, however, the Empire may collude privately during this time and then again throughout the day.
