Yes
how do I count adjacent scums with n’s and m’s, this is very struggling.
you have a general formula for arbitrary playercount and 2 scum.
Look for one for arbitrary playercount and 3 scum, then 4 scum, see if there’s a pattern.
ok I think I found one
I think the answer is 0% EV for town change my view
[(m-1-n chose 2)/(m-1 choose 2)].{[(m-2-n choose n)/(m-3 choose n)}
the period is multiplication?
Yes
yeah looks right gj
Thanks, I consider this as a win for this game.
so the way to write those nicely with tex is by using $\binom {n}{k}$
which becomes \binom {n}{k}.
\binom {m-1-n}{2} / {m-1}{2}
Doesnt work
Wait it did
takes a second to render
I’ll learn how to divide when I wake up
Goodnight
didn’t know you liked mathy stuff
I think I like statistics and probability because it’s useful in real life
Last game where people weren’t posting was better than math posting
Think about this if you don’t know it already: how can you simulate a fair coin with a biased one?